## Solution

The problem of this contest was to solve an infinite sum:

There are in general 3 different intuitive ways to find a solution to this:

`1-1+1-1+1-1+… = (1-1)+(1-1)+(1-1)+… = 0+0+0+… = 0`

`1-1+1-1+1-1+… = 1 + (-1+1)+(-1+1)+(-1+1)+… = 1+0+0+0+… = 1`

`1-1+1-1+1-1+… = x`

→`1-(1-1+1-1+1-1+…) = 1-x`

→`1-1+1-1+1-1+… = 1-x`

→`x = 1-x`

→`2x = 1`

→`x = ½`

But there are also infinitely many more ways to find a solution that you can explain. you could even reorder the sum(by taking some 1's from infinity and placing them between them at some point sooner in the sequence. This is possible, because before and after that operation the total number of 1's and -1's is still the same as before(∞)) to:`1+1-1+1+1-1+1+1-1+… = (1+1-1)+(1+1-1)+… = 1+1+1+… = ∞`

*↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓*

### List of participants with their entries:

Name | solutions found | comment |
---|---|---|

@sparkesy43 | 0 or 1 | |

@crokkon | 0 or ½ or 1 | |

@golddeck | 0 or 1 | |

@rxhector | -∞ | That's not really intuitive, but still you can get there as shown above for +∞. |

@fullcoverbetting | 0 | |

@tonimontana | ½ | But how can the sum of integers be no integer :P |

*↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓*

## Winner draw:

Congratulations @rxhector you won 1 SBI!

Of course everyone also got 10 STEM for participating(check your steem engine)!*↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓↑↓*

## Comments 6

Hi @quantumdeveloper, a small upvote and a tip from the ADDAX trading game! Round 2 has closed - please sell your tokens asap if you still hold some.

$trendotoken

Congratulations @addax, you are successfuly trended the post that shared by @quantumdeveloper!

@quantumdeveloper will receive

0.84281400TRDO & @addax will get0.56187600TRDO curation in 3 Days from Post Created Date!"Call TRDO, Your Comment Worth Something!"^{To view or trade TRDO go to steem-engine.comJoin TRDO Discord Channel or Join TRDO Web Site}are you sure about this one?

If you have an excess of (1+1-1) at the beginning, then you later have an excess of (1-1-1) which should balance it out. Doesn't allowing it to reach ∞ mean that the balance of +1s and -1s is violated?

Thanks for the STEM :)

That's what one would think would happen, but the sum here is infinite. So you can repeat the pattern that of (1+1-1) for ever without having a zone of (1-1-1).

It may fell like some -1's are lost during this process, but if you would(and could) count them you would still get the same number of 1's and -1's: infinitely many!

Congratulations @quantumdeveloper, your post successfully recieved

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